6(7+1)(7^2+1)(7^4+1)(7^8+1)=多少

2024-11-27 23:44:10
推荐回答(2个)
回答1:

(7-1)(7+1)(7^2+1)(7^4+1)(7^8+1)
=(7^2-1)(7^2+1)(7^4+1)(7^8+1)
=(7^4-1)(7^4+1)(7^8+1)
=(7^8-1)(7^8+1)
=7^16-1

回答2:

6=7-1
6(7+1)(7^2+1)(7^4+1)(7^8+1)

=(7-1)(7+1)(7^2+1)(7^4+1)(7^8+1)

=(7^2-1)(7^2+1)(7^4+1)(7^8+10

=(7^4-1)(7^4+1)(7^8+1)

=(7^8-1)(7^8+1)

=7^16-1