计算下列各式:(1)(-2a3)2+(a2)3-2a?a5;(2) 4(a+2)(a+1)-7(a+3)(a-3)+30(a-1);(3)

2025-02-25 21:15:26
推荐回答(1个)
回答1:

(1)(-2a32+(a23-2a?a5
=4a6+a6-2a6
=3a6
(2)4(a+2)(a+1)-7(a+3)(a-3)+30(a-1),
=4(a2+3a+2)-7(a2-9)+30a-30,
=4a2+12a+8-7a2+63+30a-30,
=-3a2+42a+41;
(3)(2a+b)2-(3a-b)2+5a(a-b),
=4a2+4ab+b2-(9a2-6ab+b2)+5a2-5ab,
=5ab;
当a=
1
10
,b=
1
5
时,原式=5×
1
10
×
1
5
=
1
10