求(根号3tan12°-3)⼀[sin12°(4cos²12°-2)]的值

2025-04-29 21:57:04
推荐回答(1个)
回答1:

=2根号3*(sin12/2cos12-根号3/2)/2sin12cos24

=2根号3(sin12cos60-cos12sin60)/2cos12sin12cos24

=2根号3sin(12-60)/2cos12sin12cos24

=2根号3sin48/sin24cos24

=4根号3sin48/sin48

=4根号3.