t^5⼀(t^3+t^2)dt的不定积分

2025-02-28 07:07:27
推荐回答(2个)
回答1:

∫ t^5/(t^3+t^2)dt
= ∫t^3/(t+1)dt
= ∫(t^3+t^2-t^2-t+t+1-1)/(t+1)dt
= ∫(t^2-t+1-1/(1+t))dt
= t^3/3 - t^2/2 + t -ln|1+t| + C

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回答2:

∫t^5/(t^3+t^2)dt
=∫t^3/(t+1)dt
=∫[(t+1)(t^2-t+1)/(t+1)-1/(t+1)]dt
=∫(t^2-t+1)dt-ln|t+1|
=t^3/3-t^2/2+t-ln|t+1|+C