求不定积分∫1⼀x√x dx 要详细过程解答

2025-02-26 00:57:46
推荐回答(3个)
回答1:

回答2:

回答3:

∫1/[x*x^(1/2)] *dx
=∫dx/x^(3/2)
=∫x^(-3/2) *dx
=1/(-3/2 + 1) *x^(-3/2 + 1) + C
=-2 * x^(-1/2) + C
=-2/√x + C