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碳酸钙和稀盐酸反应

2025-03-15 11:39:24

推荐回答（3个）

回答1：

126g+22.2g-139.4g=8.8g【(CO2)的质量】
根据CO2的质量可以求出
CaCl2
的质量
再用CaCl2的质量除以139.4g就是所得溶液中溶质的质量分数

回答2：

碳酸钙溶解在稀盐酸中，属于酸和盐的复分解反应：
caco3+2hcl
==cacl2+h2o+co2(气体)
实验室一般用这两种物质反应制取co2气体。

回答3：

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