c=[1928.57,2986.39]
A=[1,1]
b=168087
Aeq=[];beq=[];
vlb=[0;0];vub=[];
[x,fval]=linprog(c,A,b,Aeq,beq,vlb,vub)
c =
1.0e+003 *
1.9286 2.9864
A =
1 1
b =
168087
Optimization terminated.
x =
1.0e-011 *
0.2956
0.0680
fval =
7.7330e-009
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