设 x = tanα,则 dx = sec²α*dα。则 α 的积分范围为[π/4, π/3]那么,上面的积分变换为:=∫sec²α*dα/(secα*tan²α)=∫secα*dα/tan²α=∫(1/cosα)*dα/(sin²α/cos²α)=∫cosα*dα/sin²α=∫d(sinα)/sin²α =-1/sinα |α=π/4 →π/3=-1*[1/sin(π/3) - 1/sin(π/4)]=-1*[1/(√3/2) - 1/(√2/2)]=√2 - 2/√3