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如果分析天平的称量误差为±0.2mg

2025-03-15 17:34:21

推荐回答（1个）

回答1：

零点与结果读数都会产生正负0.1mg的绝对误差,累加绝对误差为正负0.2mg.公式请查书,W1=+-0.0002/0.0500*100%=+-0.4%;同理计算得+-0.02%（计算注意有效数字1.0000）,说明称量质量越大,相对误差越小

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