一条直线长3.8米,取中高0.33米,问弧长是几米?

2025-05-01 02:22:34
推荐回答(1个)
回答1:

(3.8/2)²+(r-0.33)²=r²
1.9²+0.33²-2*0.33r=0
r=(1.9²+0.33²)/0.66
=5.635
θ=2arctan1.9/(5.635-0.33)
=39.41°
弧长
=3.14*5.635*2*39.41/360
=3.87米