求曲线弧长

2024-12-04 13:25:01
推荐回答(1个)
回答1:

dy/dx=√sinx
s=∫(0,π)√(1+sinx)dx
=∫(0,π)√(sinx/2+cosx/2)²dx
=∫(0,π)|sinx/2+cosx/2|dx
=∫(0,π)(sinx/2+cosx/2)dx
=(-2cosx/2+2sinx/2)|(0,π)
=-2(0-1)+2(1-0)
=4