高等数学一,定积分 不定积分试题 见图 要有详细步骤

2025-02-27 06:09:40
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回答1:

4. ∫f(3x-2)dx = (1/3) ∫ f(3x-2)d(3x-2) = (1/3)F(3x-2)+C
7. 令 u=√(e^t-1), 则 t=ln(1+u^2),
dt/√(e^t-1) = 2∫<√(e^x-1),√3>du/(1+u^2)
= 2[arctanu]<√(e^x-1),√3> = 2[π/3-arctan√(e^x-1)] = π/6
π/3-arctan√(e^x-1) = π/12, arctan√(e^x-1) = π/4
√(e^x-1) = 1, x = ln2.