原式=√6÷[√(1/3)+√(1/2)] =√6÷[√(3/9)+√(2/4)] =√6÷(√3/3+√2/2) =√6÷[(2√3+3√2)/6] =√6×6/(2√3+3√2) =[(6√6)(2√3-3√2)]/[(2√3+3√2)(2√3-3√2)] =(6√6×2√3-6√6×3√2)/[(2√3)2-(3√2)2] =(36√2-36√3)/(12-18) =36(√2-√3)/(-6) = -6(√2-√3) =6√3-6√2
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