已知X=0.11001001,Y= 0.11100011,求[X+Y]补=并说明是否产生溢出

计算机组成原理的题目,哪位大侠能帮忙解答一下?
2025-03-03 09:07:55
推荐回答(1个)
回答1:

[x]补=10+x=1.10000
[-x]补=0.01111
[y]补=0.1101
[-y]=1.00110
x+y=1.01111+0.11001=0.01000
x-y=1.01111+1.11001=1.010[x]补=10+x=1.10000
[-x]补=0.01111
[y]补=0.1101
[-y]=1.00110
x+y=1.01111+0.11001=0.01000
x-y=1.01111+1.11001=1.01000