玮琦同学想探究“小灯的亮暗程度与什么因素有关”,于是找来额定电流均小于0.6A,额定电压分别是2.5V和3.

2025-03-16 09:18:45
推荐回答(1个)
回答1:

(1)向左移动滑动变阻器滑片会使灯变亮,滑动变阻器应接A接线柱,把滑动变阻器串联接入电路,电压表并联在灯泡两端,电路图如图所示.

(2)闭合开关,电压表指针反向偏转,说明电压表正负接线柱接反了,可能将电压表负接线柱可能与A接线柱误接;
(3)②从表中数据可知,实际功率等于表中前两项之积,由P=UI可知,第二项数据为通过灯泡的电流/A,如下表所示:

次数 电压/V 电流/A 实际功率/W 电阻/Ω
1 1.6 0.20 0.32 8.00
2 2.5 0.24 0.60 10.42
3 2.8 0.26 0.73 10.77
(4)由表中实验数据可知,从第1次到第3次实验,灯泡实际功率越来越大,实验发现:灯L1的亮度,第二次比第一次亮,第三次比第二次更亮,由此可知:小灯泡越亮,它的实际功率越大.
(5)L1的额定功率为2.5V,电压表选择0~3V量程;L2的额定功率为 3.8V,电压表选择0~15V量程;
所以L2替换L1,同时更换电压表量程;
(6)①灯丝电阻受温度影响较大,灯泡在不同电压下,温度不同,灯丝中电阻不同,计算平均值代表灯丝电阻无意义,梦依忽略温度对电阻的影响;
②L1换成定值电阻,能保持电阻不变,通过改变电压来改变电流能探究电流跟电压的关系.
故答案为:(1)电路图如图所示;(2)A;(3)如上表所示;(4)大;(5)电压;(6)温度;肯定.

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