java httpget 参数能带json吗

[html] view plaincopy
06-06 10:05:40.683: W/System.err(15573): java.lang.IllegalArgumentException: Illegal character in query at index 40: http://xxxxx.com/detail/?info={"type":"1","shopid":"f436701fd5c0423db53a8047894ca4e1","fields":{"name":true,"tel":true,"scores":true,"intro":true}}
06-06 10:05:40.753: W/System.err(15573): at java.net.URI.create(URI.java:727)
06-06 10:05:40.753: W/System.err(15573): at org.apache.http.client.methods.HttpGet.(HttpGet.java:75)
06-06 10:05:40.753: W/System.err(15573): at com.yulore.sdktest.http.NetUtil.get(NetUtil.java:106)
06-06 10:05:40.777: W/System.err(15573): at com.yulore.sdktest.http.BaseTask.run(BaseTask.java:25)
06-06 10:05:40.777: W/System.err(15573): at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1076)
06-06 10:05:40.777: W/System.err(15573): at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:569)
06-06 10:05:40.777: W/System.err(15573): at java.lang.Thread.run(Thread.java:856)

后来在网上查资料找到原因了：HttpGet或 HttpPost都不能传包含 " 、“{"、"}"这样的参数，需要对特殊字符进行转义，把 " 转成%22，把 { 转成%7b，把 } 转成%7d

[java] view plaincopy
RequestVo reqVo = new RequestVo();
reqVo.context = getApplicationContext();

StringBuffer sb = new StringBuffer();
sb.append("?info={\"type\":\"1\",");
sb.append("\"shopid\":\"" + shopId + "\",");
sb.append("\"fields\":{\"name\":true,");
sb.append("\"address\":true,");
sb.append("\"tel\":true,");
sb.append("\"scores\":true,");
sb.append("\"intro\":true}}");

String param = sb.toString().replace("\"", "%22")
.replace("{", "%7b").replace("}", "%7d"); //特殊字符进行转义
reqVo.requestUrl = getString(R.string.detail_api).concat(param);
reqVo.jsonParser = new ShopParser();

BaseTask task = new BaseTask(getApplicationContext(), reqVo,
handler);

ThreadPoolManager.getInstance().addTask(task);

注意：参数里面如果有 空格的话，也需要转义，否则会有问题。