已知数列{an}满足a1=1,an+1=2an+1(n∈N*).(1)计算a2,a3,a4,推测数列{an}的通项公式;(2)设Sn

2025-03-03 06:14:31
推荐回答(1个)
回答1:

(1)由a1=1,an+1=2an+1,得
a2=2a1+1=3,a3=2a2+1=7,a4=2a3+1=15.
由数列前4项猜测:an2n?1
(2)Sn=a1+a2+a3+…+an
=21-1+22-1+…+2n-1
=(2+22+23+…+2n)-n
=
2(1?2n)
1?2
?n=2n+1?n?2