用java编写一个猜数字游戏,

2025-03-15 22:48:06
推荐回答(4个)
回答1:

package day06;
import java.util.Scanner;
//猜字符游戏
public class GuessingGame {
//主方法
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int count = 0; //猜错的次数
char[] chs = generate(); //随机生成的字符数组
System.out.println(chs); //作弊
while(true){ //自造死循环
System.out.println("猜吧!");
String str = scan.next().toUpperCase(); //获取用户输入的字符串
if(str.equals("EXIT")){ //判断str是否是EXIT
System.out.println("下次再来吧!");
break;
}
char[] input = str.toCharArray(); //将字符串转换为字符数组
int[] result = check(chs,input);  //对比
if(result[0]==chs.length){ //位置对为5
int score = chs.length*100 - count*10; //一个字符100分,错一次减10分
System.out.println("恭喜你猜对了,得分:" + score);
break; //猜对时跳出循环
}else{ //没猜对
count++; //猜错次数增1
System.out.println("字符对:"+result[1]+"个,位置对:"+result[0]+"个");
}
}
}
//随机生成5个字符数组
public static char[] generate(){
char[] chs = new char[5];
char[] letters = { 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J',
'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V',
'W', 'X', 'Y', 'Z'};
boolean[] flags = new boolean[letters.length]; //1.
for(int i=0;iint index;
do{
index = (int)(Math.random()*letters.length); //0到25
}while(flags[index]==true); //2.
chs[i] = letters[index];
flags[index] = true; //3.
}
return chs;
}
//对比随机数组与用户输入的数组
public static int[] check(char[] chs,char[] input){
int[] result = new int[2];
for(int i=0;ifor(int j=0;jif(chs[i]==input[j]){ //字符对
result[1]++; //字符对个数增1
if(i==j){ //位置对
result[0]++; //位置对个数增1
}
break;
}
}
}
return result;
}
}

回答2:

java实现的简单猜数字游戏代码,通过随机数与逻辑判断来实现游戏功能
代码如下:

import java.util.InputMismatchException;

import java.util.Scanner;
public class Main {

public static void main(String[] args) {

// 产生一个随机数

int number = (int) (Math.random() * 100) + 1;
// 加入count

int count = 0;
// 在这里加入最大值,和最小值

int max = 100;

int min = 1;
while (true) {

// 键盘录入数据

Scanner sc = new Scanner(System.in);

System.out.println("请输入你要猜的数据:(" + min + "~" + max + ")");

try {

count++;

int guessNumber = sc.nextInt();

// 判断

if (guessNumber > number) {

max = guessNumber;

System.out.println("你猜大了");

} else if (guessNumber < number) {

min = guessNumber;

System.out.println("你猜小了");

} else {

System.out.println("恭喜你,花了" + count + "次就猜中了");

// 问是否继续

System.out.println("请问还要继续吗?(yes)");

sc = new Scanner(System.in);

String str = sc.nextLine();

if ("yes".equals(str)) {

// 重写赋值随机数

number = (int) (Math.random() * 100) + 1;

count = 0;

max = 100;

min = 1;

} else {

break;

}

}

} catch (InputMismatchException e) {

System.out.println("你输入的数据有误");

}

}

}

}

回答3:

import javax.swing.JOptionPane;
public class GuessNumber
{
public static void main (String args[ ])
{
System.out.println("给你一个1至100之间的整数,请猜测这个数");
int realNumber=(int)(Math.random()*100)+1;
int yourGuess=0;
String str=JOptionPane.showInputDialog("输入您的猜测:");
yourGuess=Integer.parseInt(str);
while(yourGuess!=realNumber) //循环条件
{
if(yourGuess>realNumber) //条件代码
{
str=JOptionPane.showInputDialog("猜大了,再输入你的猜测:");
yourGuess=Integer.parseInt(str);
}
else if(yourGuess{
str=JOptionPane.showInputDialog("猜小了,再输入你的猜测:");
yourGuess=Integer.parseInt(str);
}
}
System.out.println("猜对了!");
System.out.println("这个数是"+realNumber);
}

回答4:

新手炒沥青初期需要投入多少资金?
我这边是3W,最低没有门槛,你就是入两千都可以玩,但问题是两千只能操作1手,而且没有抗风险资金了,你买了之后只要点位瞬间波动一个点你就直接平仓了,没法玩的,所以我都是入金五万以上玩的。

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