求下列函数近似值cos29°,ln1.01,arctan1.05

2025-02-27 07:32:27
推荐回答(2个)
回答1:

cos29°≒cos30°=√3/2
ln1.01≒ln1=0
arctan1.05≒arctan1=π/4

回答2:

cos29°~cos30°=√3/2
ln1.01~ln1=0
arctan1.05~arctan1=π/4