x= (x-1) + 1∫x√(x-1) dx=∫(x-1)√(x-1) dx +∫√(x-1) dx=∫(x-1)^(3/2) dx +∫(x-1)^(1/2) dx=(2/5)(x-1)^(5/2) +(2/3)(x-1)^(3/2) + C
不好意思，我看看。早忘了
