-∫2p/(256-p²)dp=∫[1/(256-p²)]d(-p²)=∫[1/(256-p²)]d(256-p²)=ln|256-p²|+C1所以，e^[-∫2p/(256-p²)dp]=e^[ln|256-p²|+C1]=e^C1·[e^ln|256-p²|]=C·|256-p²|
如图所示。
