tan(a-π⼀4)=1⼀2求(sina-2cosa)⼀(sina+cosa)的值

2025-03-10 16:11:11
推荐回答(1个)
回答1:

tana=tan([a-π/4)+π/4]

=[tan(a-π/4)+π/4]/[1-tan(a-π/4)tan(π/4)]

=(1+1/2)/(1-1/2)

=3

(sina-2cosa)/(sina+cosa)

=(tana-2)/(tana+1)

=1/4

谢谢