main() { int a=1,*p,**pp; pp=&p; p=&a; a++; printf("%d,%d尀n",a,*p,**pp); } 求输出结果,详细解及思路

2025-03-03 08:00:03
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回答1:

a++ => a = a+1 => a=2

p=&a => *p = 2

pp=&p => *(*pp) = *p =2