已知lx-8yl+2(4y-1)눀+3l8z-3xl=0,求x+y+z的值.(注:

2025-04-28 04:15:03
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回答1:

由题意得:x-8y=0,4y-1=0,8z-3x=0
x-8y=0解得x=8y
4y-1=0解得y=1/4
8z-3x=0解得z=3/8x
将y=1/4代入x=8y得:x=2
将x=2代入z=3/8x得z=3/4
所以x=2,y=1/4,z=3/4
x+y+z=2+1/4+3/4=3