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13问答网 > 因式分解：3x的三次方加7x的平方减4等于多少

因式分解：3x的三次方加7x的平方减4等于多少

2025-03-15 22:14:22

推荐回答（2个）

回答1：

f(x)= 3x^3+7x-4
f(-1) =0
3x^3+7x-4=(x+1)(3x^2+ax-4)
coef. of x
-4+a=7
a=11

3x^3+7x-4
=(x+1)(3x^2+11x-4)
=(x+1)(3x-1)(x+4)

回答2：

3x³+7x²-4=3x³+3x²+4x²-4=3x²(x+1)+4(x+1)(x-1)=(3x²+4x-4)(x+1)=(3x-2)(x+2)(x+1)

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