若x1、x2是一元二次方程2x^-4x+1=0的两个实数根,则x1⼀x2+x2⼀x1的值是

2025-02-27 23:28:12
推荐回答(1个)
回答1:

唯达定理:x1+x2=2,x1x2=1/2
→x1²+x2²=(x1+x2)²-2x1x2=3
→x1/x2+x2/x1=(x1²+x2²)/x1x2=6