解∶(1)设BC=kx﹢b.
将点B,C的坐标代入,
得k=﹣1,b=5.
∴y=-x+5
将点C,D两点坐标代入,
得b=﹣6,c=5.
∴y=x²-6x+5
﹙2﹚MN=﹣x+5-﹙x²-6x+5﹚
=-x²﹢5x
=-﹙x²-5x﹚
=-﹙x-5/2﹚²+25/4
∴MNmax=25/4
(3)
http://wenku.baidu.com/link?url=kLg6eNA38dqfvB5vywqNZ_5xut-3XWHUSYHBpChREFoKaOtY59XL17ynpluTTB7VViWa9jKCZONjhwuK4ovO8O4PTpOOOKXcPdSj7ZmvhvK
这么简单的题,