x—y=1,z—y=-1,求x的平方加上y的平方加上z的平方减去xy—yz—xz的值.

2025-03-07 03:35:21
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回答1:

x =1+yz =-1+yx2+y2+z2-xy-yz-xz的值x2+y2+z2-xy-yz-xz=(1+y)2 +y2+(-1+y)2-(1+y)y-y(-1+y)-(
1+y)( -1+y)=1+ y2+2y+y2+1+ y2-2y-1y-
y2+1y- y2+1-1y+1y- y2=3