设z=(x+y)2,而x=sint,y=cost,求dz⼀dt=

2025-02-26 03:29:56
推荐回答(3个)
回答1:

z=(sint+cost)^2
=1+sin2t
所以z'=2cos2t
所以dz/dt=2cos2t

回答2:

回答3:

x=sint
y=cost

z=(x+y)^2
=(sint +cost)^2
= 1+ sin2t
dz/dt = 2cos2t