y' = [(1/2)/√(1-2x)]*(-2) = -(1-2x)^(-1/2), y" = [(-1)²(1/2)](1-2x)^(-3/2), y"' = [(-1)³(1/2)(3/2)](1-2x)^(-5/2) = [(-1)³(3!!/2²)](1-2x)^(-5/2), ……, y^(n) = ……(留给你)
n阶求导 现求一阶求导及二阶求导,然后归纳
(1-2x)∧(-3/2)吧?