接下
因为m是方程x^2+3x-1=0的一个根,
所以m^2+3m-1=0 即
m^2+3m=1
化简代数式 (m-3)/(3m^2-6m)÷[m+2-5/(m-2)]
=(m-3)/(3m^2-6m)÷[(m^2-4-5)/(m-2)]
=(m-3)/[3m(m-2)]×(m-2)/(m^2-9)
=(m-3)/[3m(m^2-9)]
=(m-3)/[3m(m+3)(m-3)]
=1/[3(m^2+3m)]
=1/(3×1)
=1/3
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