本题应注意绕y=-1旋转
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V = π∫<0, 1> (1+e^x)^2 dx - 1^2π*1= π∫<0, 1>[1+2e^x+e^(2x)]dx - π= π[x+2e^x+(1/2)e^(2x)]<0, 1> - π= π[2(e-1)+(1/2)(e^2-1)]
