[1-(2⼀3+1⼀5)×1⼀13]+7⼀10脱式计算?

2025-03-07 14:28:15
推荐回答(2个)
回答1:

[1-(2/3+1/5)×1/13]+7/10


=[1-(10/15+3/15)×1/13]+7/10


=[1-13/15×1/13]+7/10


=[1-1/15]+7/10


=14/15+7/10


=28/30+21/30


=49/30

回答2: