(1)∵i2=-1,∴i3=i2?i=-1?i=-i,i4=i2?i2=-1?(-1)=1,(2)①(2+i)(2-i)=-i2+4=1+4=5;②(2+i)2=i2+4i+4=-1+4i+4=3+4i;(3)∵(x+y)+3i=(1-x)-yi,∴x+y=1-x,3=-y,∴x=2,y=-3;(4) 1+i 1?i = (1+i)(1+i) (1?i)(1+i) = (1+i)2 2 = 2i 2 =i.