t的6次方-9乘t的3次方+8怎么分解

2025-02-24 20:21:12
推荐回答(2个)
回答1:

t的6次方-9t的3次方+8
=(t的3次方-1)(t的3次方-8)
=(t-1)(t的2次方+t+1)(t-2)(t的2次方+2t+4)

回答2:

t^6-9t^3+8=(t^3-1)(t^3-8)=(t-1)(t^2+t+1)(t-2)(t^2+2t+4)