第三题的第二小题怎么做?数学学霸帮帮忙

2025-04-27 10:17:52
推荐回答(1个)
回答1:

x(y-3)-(2y-6)
=x(y-3)-2(y-3)
=(y-3)(y-2)
(x+y)^3-(x-y)^2(x+y)
=(x+y)[(x+y)^2-(x-y)^2]
=(x+y)[(x+y+x-y)(x+y-x+y)]
=(x+y)*2x*2y
=4xy(x+y)
x(x^2-xy)-(4x^2-4xy)
=x^2(x-y)-4x(x-y)
=x(x-y)(x-4)