求证D(aX+b)=a눀D(X)

2025-02-27 06:33:26
推荐回答(1个)
回答1:

证明:E(ax+b)=aE(x)+b
D(x)=E(x^2)-(E(x))^2
D(ax+b)=E((ax+b)^2)-(E(x))^2
=E(a^2x^2+2abx+b^2)-(E(ax+b))^2
=a^2*E(x^2)+2ab*E(x)+b^2-(aE(x)+b)^2
=a^2*E(x^2)+2ab*E(x)+b^2-(a^2(E(x))^2+2abE(x)+b^2)
=a^2*E(x^2)-a^2(E(x))^2=a^2(E(x^2)-(E(x)^2)
=a^2*D(x)
可以吗?