[sin(π+3α)cos(-α+3π)sin(α-3π/2)cos(11π/2-α）] ÷ [cos（3α+9π/2)sin(-α-π）tan（-π+α）tan(π/2-α）]=[-sin3α(-cosα)cosα(-sinα)] ÷ [(-sin3α)sinαtanαcotα)]=(-sin3αcos²αsinα) ÷ (-sin3αsinα)=cos²α
(cosα)*(cosα)
