短周期中常见金属X、石墨和二氧化钛(TiO 2 )按比例混合,高温下反应得到的化合物均由两种元素组成,且

2025-03-16 18:16:59
推荐回答(1个)
回答1:

(1)能和盐酸和氢氧化钠溶液反应的金属单质是铝,铝是13号元素,铝离子原子结构示意图为:



,铝的最高价氧化物的水化物是氢氧化铝,氢氧化铝在碱性溶液中的电离方程式为:Al(OH) 3 =H + +AlO 2 - +H 2 O,故答案为:



,Al(OH) 3 =H + +AlO 2 - +H 2 O;
(2)a.石墨烯的结构和多个苯环相连的结构相似,苯中各原子处于同一平面上,根据苯的结构知,
石墨烯分子中所有原子可以处于同一平面,故正确;
b.石墨烯中的碳碳键的键角是120°,故错误;
c.石墨烯是单质,化合价为0,故错误;
d.石墨烯是单质,所以它既不是电解质也不是非电解质,故错误;
e.石墨烯是平面结构,金刚石是空间网状结构,故错误;
f.石墨烯虽然是分子晶体,但熔点不很低,故错误;
g.石墨属于分子晶体,分子间存在分子间作用力,所以从石墨剥离得石墨烯需克服范德华力,故正确;
故选ag;
(3)原子核外有多少个电子就有多少种运动状态,有多少种能级就有多少种不同能量的轨道,钛是22号元素,其核外有22个电子,所以有22种运动状态,有1s 2s 2p 3s 3p 3d 4s共7种不同能量的轨道,故答案为:22;7;
(4)高温条件下,铝、石墨和二氧化钛反应生成氧化铝和碳化钛,反应方程式为 4Al+3TiO 2 +3C
 电解 
.
 
2Al 2 O 3 +3TiC,故答案为:4Al+3TiO 2 +3C
 电解 
.
 
2Al 2 O 3 +3TiC.

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