若要|x+y-3|*(x-y-2)^2=0
因绝对值和平方都大于等于0,则有
x+y-3=0
x-y-2=0
即
x+y=3
x-y=2
(x+y)*(x-y)=3*2=6
那说明x+y-3等于0 x-y-2也等于0 所以x+y等于3 x-y等于2 所以答案是6
|x+y-3|+(x-y-2)^2=0
=>
x+y=3 (1) and
x-y=2 (2)
(1)+(2)
x=5/2
from (1)
5/2+y=3
y=1/2
x+y= 5/2 +1/2 =3
x-y = 5/2 -1/2 =2
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