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13问答网 > 如图所示，单摆摆球的质量为m，做简谐运动的周期为T，摆球从最大位移A处由静止开始释放，摆球运动到最低

如图所示，单摆摆球的质量为m，做简谐运动的周期为T，摆球从最大位移A处由静止开始释放，摆球运动到最低

2025-03-16 04:09:00

推荐回答（1个）

回答1：

A、摆球从最大位移A处由静止开始释放，摆球运动到最低点B，根据动能定理得：
W_G=

1

2

mv²-0，故A正确．
B、某个力的功率应用力乘以力方向上的速度，摆球运动到B时的速度方向是水平的，所以重力的瞬时功率是0，故BC错误．
D、摆球从A运动到B的过程中重力的平均功率p=

w

t

=

2mv2

T

，故D错误．
故选：A．

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