f(x)=2sin(2x+π/6)+m+1记t=2x+π/6，t∈[π/6,2π+π/6]f(t)=2sin(t)+m+1f(t)的单调递增区间为:t∈[π/6,π/2]或t∈[3π/2,2π+π/6]此时:x∈[0,π/6]或x∈[2π/3,π]即所求。
