已知sin(3π+θ)=lg1⼀(10开3次方0{cos(π+θ)⼀cosθ[cos(π-θ)-1]}+{ cos(θ-π)⼀cos(π-θ)+cos(θ

2025-03-01 06:21:30
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回答1:

sin(3π+θ)=lg1/(10开3次方)得:-sinθ=-1/3;则cos^2θ=8/9;{cos(π+θ)/cosθ[cos(π-θ)-1]}+{ cos(θ-2π)/cos(π-θ)+cos(θ-2π)}
={-cosθ/cosθ[-cosθ-1]}+{cosθ/-cosθ+cosθ}代数据,不过感觉你这题有点不对劲~~