显然包括啊,先根据倍角公式,进行降次,得f(x)=m-mcos2x-√3msin2x+n =-2msin(2x+π/6)+m+n定义域为[0,π/2],2x+π/6取值范围是[π/6,7/6π],f(x)值域是[n-m,2m+n],所以m=3,n=-2.g(x)=3sin(x+10°)-4cos(x+40°)
sin(2X+π/6)范围是(-1/2~1)所以带入f(x)=-2msin(2x+π/6)+m+n 中得(m+n-2m~m+n+2m)