4sin^2a+2sinacosa-cos^2a
=(4sin^2a+2sinacosa-cos^2a)/(sin^2a+cos^2a)
=(4tan^2a+2tana-1)/(tan^2a+1) (分子分母同时除以cos^2a,这类题都这么做的)
=(4*3^2+2*3-1)/(3^2+1)
=(36+6-1)/(9+1)
=41/10
*这是乘号
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我认为应该是这样的4sin^2a+2sinacosa-cos^2a
=(4sin^2a+2sinacosa-cos^2a)/(sin^2a+cos^2a)
=(4tan^2a+2tana-1)/(tan^2a+1) (分子分母同时除以cos^2a,这类题都这么做的)
=(4*3^2+2*3-1)/(3^2+1)
=(36+6-1)/(9+1)
=41/10