已知3X-4Y-Z=0,2X+Y-8Z=0,求x2+y2-z2⼀xy+yz的值

2025-05-01 12:35:29
推荐回答(1个)
回答1:

24x-32y-8z=0

(24x-32y-8z)-(2x+y-8z)=22x-33y
y=2x/3;
8x+4y-32z=0
8x+4y-32z+3x-4y-z=11x-33z=0
z=x/3
x=3z
y=2z
(x2+y2-z2)/(xy+yz)=(3*3+2*2-1*1)/(3*2+2*1)=3/2