求解一道数学因式分解题,要写过程噢~

2025-03-13 09:33:08
推荐回答(3个)
回答1:

4a-1+b^2-4a^2
=b^2-1+4a-4a^2
=b^2-(4a^2-4a+1)
=b^2-(2a-1)^2
=(b+2a-1)(b-2a+1)

回答2:

原式=b^2-(4a^2-4a+1)
=b^2-(2a-1)^2
=(b+2a-1)(b-2a+1)

回答3:

4a-1+b2-4a2=b2-(4a2-4a+1)=b2-(2a-1)2=(b+2a-1)(b-2a+1)