两边同乘x-2得1=（x-1）-3（x-2）1=x-1-3x+61=5-2xx=2（舍去）原方程无解
1/(x-2)=(1-x)/(2-x)-31/(x-2)-(1-x)/(2-x)=-31/(x-2)-(x-1)/(x-2)=-3(2-x)/(x-2)=-32-x=-3x+63x-x=6-22x=4x=2检验: x=2是原方程的增根,所以原方程无实根.
