(2x+3)²-2(2x+3)(3x-2)+(3x-2)²
=[(2x+3)-(3x-2)]²
=(2x+3-3x+2)²
=(-x+5)²
=(x-5)²
=x² -10x+25
(16x^4+y^4)(4x^2+y^2)(2x-y)(2x+y)
=(16x^4+y^4)(4x^2+y^2)(4x^2-y^2)
=(16x^4+y^4)(16x^4-y^4)
=256x^8-y^8
原式=[(2x+3)-(3x-2)]^2=[-x+5]^2=x^2-10x+25
它是一个完全平方式,原式=(2x+3-3x+2)^2=(5-x)^2