(x+y)*(x^2-xy+y^2)-(x-y)*x^2+xy+y^2)

2025-03-10 20:35:04
推荐回答(2个)
回答1:

答案 2y三次方

(x+y)*(x^2-xy+y^2)-(x-y)*(x^2+xy+y^2)
给多项式里加条件 变为 完全平方公式
得(x+y)((x-y)²+xy)-(x-y)((x+y)²-xy)(这能看懂吗 看不懂你把括号拆了 和原式一样的)
(拆大括号 ,大括号没打出来 就是外面的括号)
(x+y)(x-y)²+xy(x+y)+(x-y)xy-(x-y)(x+y)²
提取公因式xy和(x+y)(x-y)
=xy(x+y+x-y)+(x+y)(x-y)(x-y-x-y)
化简
2x²y-2y(x²-y²)
得2x²y-2x²y+3y³
得3y³
声明我没有抄袭 因为我打字慢!

回答2:

(x+y)*(x^2-xy+y^2)-(x-y)*(x^2+xy+y^2)
=(x^3+y^3)-(x^3-y^3)
=x^3+y^3-x^3+y^3
=2y^3